(x^2+7x+12)(x-5)=0

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Solution for (x^2+7x+12)(x-5)=0 equation: 


Simplifying
(x2 + 7x + 12)(x + -5) = 0

Reorder the terms:
(12 + 7x + x2)(x + -5) = 0

Reorder the terms:
(12 + 7x + x2)(-5 + x) = 0

Multiply (12 + 7x + x2) * (-5 + x)
(12(-5 + x) + 7x * (-5 + x) + x2(-5 + x)) = 0
((-5 * 12 + x * 12) + 7x * (-5 + x) + x2(-5 + x)) = 0
((-60 + 12x) + 7x * (-5 + x) + x2(-5 + x)) = 0
(-60 + 12x + (-5 * 7x + x * 7x) + x2(-5 + x)) = 0
(-60 + 12x + (-35x + 7x2) + x2(-5 + x)) = 0
(-60 + 12x + -35x + 7x2 + (-5 * x2 + x * x2)) = 0
(-60 + 12x + -35x + 7x2 + (-5x2 + x3)) = 0

Combine like terms: 12x + -35x = -23x
(-60 + -23x + 7x2 + -5x2 + x3) = 0

Combine like terms: 7x2 + -5x2 = 2x2
(-60 + -23x + 2x2 + x3) = 0

Solving
-60 + -23x + 2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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